Archimedess Principle Submitted by: Physics Class: 210 research lab section: B Date Performed: 3-13-02 Date Submitted: 3-20-02 Lab match: Sample Calculations 1. Weight = mass x 9.80 g/cm^3 W= 45g x 9.80 N W= 44,100 dynes 2. bright describe (calculated) = pitch in air load in piss BF = 44,100 dynes 38710 dynes BF = 5390 dynes 3. Volume of Water = radius^2 x length V= (.63cm) (4.65cm) V= 5.80 cm 4. Buoyant army ( careful) = mass in air/ density BF= (44,100 g) / (7.76 g/cm^3) BF= 5684 cm^3 5. % difference = BF calculated BF measured/ BF measured % difference = 5390 5684 / 5684 % difference = 5.4 % 6. meanness = Mass / Volume Density = 45 g / 5.80 cm^3 Density = 7.76 g/cm^3 7. Volume of timberwind instrument = length x width x height V = (7.62cm) (7.63cm) (3.86 cm) V = 224. 42 cm^3 Questions 2.) Because an overweight person evokes more smooth when ill-treatping into a pool. By displacing more fluid, the person creates a greater blessed force making it easier for him to swim.
5.c) By placing a bombing into the water with a floating rod into its deep rounded cavity it is quite easy to determine the condition of the battery. The dilute battery will have a much high density than that of a highly charged battery. From the observation of how the battery floats you can tell its condition.
8.) We were able to go the volume of displace water in Part II quite easily. scratch line we placed a large tupperware container on the table and in it a little container filled to the top with water. When the block of wood was placed in the container, water fell come on of the small container into the larger container. By placing the water which fell out of the smaller container into a cylinder, you are able to measure the volume of displaced water.
9.) No I did not use Archimedess principal to find the densities. I used the density formula of dividing the mass by the volume. We find the densities and compare them to the densities of water to help understand the chemical mechanism of buoyant force.
Discussion         In part both of the lab dealing with Archimedess principle, we were comparing the buoyant force of a block of wood to its weight in dynes. The first step of the operation dealt with measuring the quantity of displaced water. We did this using two containers, unrivaled small and one large, and filled the small container to the brim with water.
By placing the block of wood in the small container and using a graduated cylinder, we were able to find the amount of water displaced by the block.
        The next step of the procedure was to actually compare the weight of the wood to the buoyant force of the wood in water using Archimedess principal. According to Archimedess principal by multiplying the amount of water displaced by the wood by 980 g/cm^3 we could calculate exactly how much buoyant force the wood had in water. We then calculated the share difference by using the calculated buoyant force and subtracted it from the weight of the wood in dynes, divided it by the weight in dynes and came up with a percent error of 6.8%.
        The 3rd and final procedure used in part two of the lab was finding the volume of the wood to figure out its density in water. By multiplying the blocks length time its width and height we were able to figure out the woods volume. By dividing this by the woods mass, we shew
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